Fragen im Vorstellungsgespräch: Software engineer in Bengaluru, Indien

Hello, given that they had collected your photograph and salary slips, I would say you have a real good chance of receiving an offer with Shell. All the best!

Hi ABC can u share what kind of techincal question they have asked, r they asked to write program or only oral with usecases? as i am having my interview on next week for java developer.

Hi, I understand they are checking the background as part of enhanced screening via a 3rd party agency? How long does this process take? What to expect? And does the status of the application in the Shell portal change regularly? I see it as Completed Assessment. Thanks for a reply.

For me, they obtained declaration to carry out BG check 10 days prior to joining and I was not contacted further in this regard. For some colleagues, third party requested for additional docs. Am not sure on the status of my application on shell portal.

Hi I have been scheduled for F2F interview for QA position on June 6th. Can anyone help me in knowing what kind of questions might come on my way in both Professional Assessment and Structured Assessment If anyone from QA had experience with Shell interviews please do reply.

Hi there XYZ, I suppose your interview is already done, could you please assist me in Professional and Structural interview. what scenarios were asked and what all technical questions were put across. Any tip that i should keep in mind. Thanks in advance.

Being low paid, will it damage my case if i ask for a 50% hike in case selected? I am awaiting result of final round in a week's time.

Usually, Shell has a lower and upper salary limit for a specific salary group. No matter how low your current salary is, you ll be mapped to atleast the lower limit. In my case, I did not have to negotiate, but you may do so based on your requierments.

i completed my final assessment on 8 th August. Dint receive any updated till now. please guide.

Hi, I also attended interview in Shell this Wednesday, everything went fine.. but after all the rounds Hr didn't collect photograph or any Documents.. She just told me that within 2 weeks you will be getting result? Can you tell me, is that any chance that they will select me?

Same here, 2 rounds f2f completed, hr said they will get back to me within 2week, but they didn't collected any doc or photo, will I have chance of getting offer?

Hi, Did you get ur call letter after your process was done.

Hii, did u get ur offer letter?

After final round of interview how many weeks they will take to tell the result?

Did you get the offer and how long it took?

Hi XYZ, did you get your interview feedback. How long they are taking to tell the feedback after attending the final assessment.

Hi there, How long they take to give the feedback after the final assessment. I finished the final assessment on Oct 8, it's been a month now, still no update on it.

Does shell confirm the outcome of interview or do we just need to wait for some indefinite time for a call from HR otherwise assume rejection? If this is the policy then how long should we wait?

#include int main(){ int i,no,no1; printf("\n Enter number : "); scanf("%d",&no); if(no 26){ printf("A"); no1 -= 26; } if(no == 0) no = 26; // code for finding the particular alphabet from A-Z for(i = no; i <=no; i++){ printf("%c",'@'+i); } } return 0; }

import java.util.Scanner; public class Alpha { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(),temp=0, count = 0,rem=0; String alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; if(n26){ count = n/26; rem = n%26; if(rem != 0){ for (int i = 0; i < count; i++) { System.out.print("A"); } temp = n - count*26; System.out.print(alpha.charAt(temp-1)); } else{ for (int i = 0; i < count-1; i++) { System.out.print("A"); } System.out.println("Z"); } } } }

#include int main() { int num; printf("enter a number\n"); scanf("%d",&num); while(num>26) { printf("A"); num=num-26; } if(num<=26) { printf("%c",num+64); } return 0; }

#include int main() { int n; printf("Enter a Number ::: "); scanf("%d",&n); int tmp =n/26; int val=0; while (tmp>0) { tmp--; if (tmp==0 && n%26==0) { printf("Z"); val++; break; } if (!(tmp<0)) { printf("%c",65); } } if (val!=1) { printf("%c", (n%26)+64); } printf("\n"); }

By mistake I pressed down vote. Nice code - > PoornimaB

import java.util.*; public class Program3 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); if(n26)&&(n52)&&(n<78||n<=78)) { int a=n%26; a--; int b=65+a; char ch=(char)b; if(n==78) ch='Z'; System.out.println("AA"+ch); } } }

import java.util.*; public class Program3 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); if(n26)&&(n52)&&(n<78||n<=78)) { int a=n%26; a--; int b=65+a; char ch=(char)b; if(n==78) ch='Z'; System.out.println("AA"+ch); } } }

LANGUAGE OF MY CODE IS JAVA BUT IT WILL HELP YOU TO GET LOGIC public class part2 { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println("enter a number"); int n=scan.nextInt(); int fact; fact=n/26; if(n%26==0){ fact=fact-1; } for(int i=0;i

LEFT PORTION OF ABOVE CODE IS HERE for(int i=0;i

static string Alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; public static void numToString(int num) { if(num<=26) { Console.Write(Alpha[num - 1]); return; } Console.Write('A'); numToString2(num - 26); }

#include main() { int i,k,n,m,count=0; scanf("%d",&n); for(i=2;i<=n;i++) { for(k=0;k<=i;k++) { if((i%k==0)) count++; } if(count==2) m=2*i+1; count==0; for(k=0;(m!=0)&&(k<=m);k++) { if((m%k==0)) count++; } if(count==0) printf("%d",m); } }

#include main() { int i,n,p,k,count=0,plus=0; printf(:enter the no\n"); scanf("%d",&n); for(i=2;i

#include int prime(int num) { int i,c=0; for(i=2;i

Answer is in java :100% correct public class ProgramDemo { public static void main(String[] args) { System.out.println("Enter the value :"); Scanner read = new Scanner(System.in); int number = read.nextInt(); for(int i=2;i<=number;i++){ if(Prime(i)){ if(Prime(2*i+1)){ System.out.print(" "+i); } } } } static boolean Prime(int a) { int temp, c; for (c = 2; c <= a - 1; c++) { temp = a % c; if (temp == 0) { return false; } } if (c == a) { return true; } return false; } } I Hope its helpful for you :) Plese give me one like for it ....

Excellent bro

import java.util.Scanner; public class HelloJava { public static void main(String args[]) { int i,flag=0; for( int x = 2 ;x<100 ;x++) { flag=0; for(i=2;i<=x-1;i++) { if(x%i==0) { flag = 1; break; } } if(flag==0) { for( i = 2; i

Can anyone please explain the logic?

#include #include void main() { int i; printf("Enter no. of terms \n"); for(i=2; i<=50 ; i= 2*i+1) { printf("\n %d", i); } return 0; }

Exact answer is 30 coins. Since each time monkey kills one person.

This is correct for 10 coins as well

suppose initial coins were 30 then money steals one coin so #coins = 29. now 10 people are there and the no of coins are 1 less than equal share i.e if 30 coins were there 3 per person but only 29 coins are there. so this case is ok. lets look for 9 people, since monkey kills one guy. now for 9, 29 is not one short of equal share because 9*3 ==27 , 9*4 == 36 neither of which satisfy the condition. so 30 cannot be the original coins. same thing for 8,7,6,.. 10 coins cannot be the original. Please read the question carefully.. this hint will be the closest to the answer, keep this part of the question in mind : "each time a person dies the no of coins are always one short of equal share".

I think it is 2520 i.e.LCM of 2-10

I think 2520 is perfect

sweet:-) nice ans. also think of 10! since the numbers in factorial are the remaining people after each iteration(2x3x4x5x6x7x8x9x10) and they form factors of the factorial number. and the factorial - 1 will always be one less than equal share. this fits the solution:-)

Multiples of 2520 will be the answer

Yes any Common multiple of the factors is a solution.

Answer is pretty simple: m%10=0 -----case 1 Lets assume n=m-1 Since the remainder is always same , when n is divider by any number from 10 to 1.. n%10 = n%9=.........=1 That means n+1 is completely divisible by all numbers from 10 to 1.. (Since it gives common remainder).. n + 1= Lcm of (1 to 10) = 2520 But we assumed n = m-1, so m -1+1 =m = 2520

Ader Lee: Shouldn't it be: f(n) = Σf(i) + (n-1), , where i = 1 to n-2, n>2 (i ranges from 1 to n-2, not n-1)

f(1) = 0 and f(i) = i - 1 + sum_{i = 0}^{i - 1} f(i) Writing it down helps to find the sum: f(1) = 0(0) f(2) = 1 + 0(1) f(3) = 2 + 1 + 0(3) f(4) = 3 + 3 + 1 + 0(7) f(5) = 4 + 7 + 3 + 1 + 0(15) The first term(i - 1) equals the number of second terms and the second terms are the sum of 2 powers - 1 from 0 to (i - 2) so f(i) = 2^{i - 1} - 1

Also there is a neat normal form to generate all variations. For the sake of simplicity I show it for i = 4: Start from 1 + 1 + 1 + 1 and for j in 1 to i - 1 add together j and (j + 1) and write down the numbers and mark the added number in the next iteration. | | | 2 + 1 + 1 1 + 2 + 1 1 + 1 + 2 From the marked numbers to (last - 1) run j and do the same as before. The first generates 2 more, the second 1 more and the last one none. gen by first | | 3 + 1 2 + 2 gen by second: | 1 + 3 We could also generate the one element sum(4) from the first one but it's not needed in the problem. Also this representation looks nicer in a tree form but I can only type text here.

The marks moved to the begining of the rows since the forum probably has some nice mangling algorithm. I hope you can figure out how the normalisation works. Might post some python code which does this later.

a coin change problem with little modification will do .

365.25 / yr I wouldn't say 365/ 366 leap year. Jain has a point.^

It's either 364.25 or 366.25 depending on whether the earth spins in the same direction as it goes around the sun or not (I don't remember which it is and can't deduce it from the information that's available to me without looking it up). Imagine if the Earth did not spin at all on its axis so it would seem as if a year was equivalent to one day. It will take the Earth rotating either 264.24 or 366.25 times depending on the direction to seem like the 365.25 days that it does take.

Every year it takes 365.25 rotations but while making calendar we ignore that 0.25 for 3 years and add an extra day in 4th year.

<b>365.25 is WRONG!!!</b> Actually <b>Anonymous</b> is right! Just think about this (lay it out on your desk): <ul> <li>How many days would there be if the earth would not revolve around its axis?</li> <li>How many days would there be if it turned once around it's axis?</li> <li>Now do again one, change the direction the earth revolves it's axis, but keep going the same direction around the sun ...</li> </ul> The concrete right answer is 366.25 Here you find details on the exact number (with other proof): :)

This question makes no sense.

It's other way around, only when earth complete one round, we call it a year. To make human calculations easy, we introduced leap yrs.

366 rotations per year with respect to a distinct star.

366 rotations in a no leap year with respect to distinct star.

fake company,they ask 1.5 to 2 for candidate,the r using an old deleated web site and making money there is no such company,so fresher dont join,also i meet an employee who is working there,he gave money and joined,starting 2 months had got 18k,then they r not giving salary.they will tel 3.60pa but the will not give it-seams there r only 30 to 40 member in this company they r making money,after some days they will close this company and start with new comany by giving their name,so dont join,if they call u then inform directly to the policestation,os that new canditates will not be cheated........they r only choosing fresher candidates,go through reviews and dont see starting review,see at the last.already joined candidates r not getting salary and no 1.5 back also.please share this to ur friends....they r playing with career

fack company go through overview,u can see no founder details,no revenue details,nothing is there dont join fack,fake call letter,fake bond,fake salary,fake company.....dont get cheated

I Think don't waste your money and time by this company .Its fake company if you should search on google any company having some wiki and pages . but it does not have any information company and simply open website .My suggestion for fresher don't waste your parents money .if you have any doubt search addresses of different locations in various countries .

I Think don't waste your money and time by this company .Its fake company if you should search on google any company having some wiki and pages . but it does not have any information company and simply open website .My suggestion for fresher don't waste your parents money .if you have any doubt search addresses of different locations in various countries .

I have facing same issues ,They demanded 2 lakhs k initially 30 k and i paid 30 k .But even i do not believe this company. interviewer also they asked 4 to 5 questions to java and then Hr round it will done 2 min .studs they are paying 3 they pay 15 to 18 k then ?????? .do not waste your parents money by giving that frauds Hrs .Thinks about yours parents their parents pain and do not lose your future. Be careful my brothers and sisters .

I have facing same issues ,They demanded 2 lakhs initially 30 k and i paid 30 k .But even i do not believe this company.In interview they asked 4 to 5 questions to java and then Hr round it will done 2 min . They are paying 2 to 3 months 15 to 18 k then ?????? .do not waste your parents money by giving that frauds Hrs .Think about yours parents their pain and do not lose your future. Be careful my brothers and sisters .